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For the LED driver chip debugging technology is mainly the following aspects

     1, chip fever
     This is mainly for the high voltage driver chip with a built-in power modulator. If the current consumed by the chip is 2mA, the voltage of 300V is applied to the chip. The power consumption of the chip is 0.6W, which of course will cause the chip to heat up. The maximum current of the driver chip comes from the consumption of the driving power mos. The simple calculation formula is I=cvf (taking into account the charging efficiency of the charging, the actual I=2cvf), where c is the cgs capacitor of the power MOS transistor and v is the power transistor The gate voltage of the pass-through time, so in order to reduce the power consumption of the chip, must find ways to lower c, v and f. If c, v, and f cannot be changed, then consider ways to divide the power consumption of the chip into devices outside the chip, taking care not to introduce extra power consumption. Simply, consider better cooling.
     2, power tube heating
     Power tube power consumption is divided into two parts, switching loss and conduction loss. It should be noted that in most applications, especially LED mains-driven applications, switching damage is much greater than conduction losses. The switching loss is related to the power supply's cgd and cgs and the chip's driving ability and operating frequency. Therefore, to solve the power transistor heating can be resolved from the following aspects: a: can not be selected based on the size of the on-resistance MOS power transistor, Because the smaller the internal resistance, the larger the capacitance of cgs and cgd. Such as 1N60's cgs is about 250pF, 2N60's cgs is about 350pF, 5N60's cgs is about 1200pF, the difference is too big, when choosing the power tube, enough is enough. b: The rest is the frequency and chip driver capability. Here only the frequency effect. The frequency and the conduction loss are also proportional to each other. Therefore, when the power transistor is heated, the first thing to consider is whether the frequency selection is a bit high. Try to reduce the frequency! However, it should be noted that when the frequency is reduced, in order to obtain the same load capacity, the peak current must be larger or the inductance becomes larger, which may cause the inductor to enter the saturation region. If the inductor saturation current is large enough, consider changing the CCM (Continuous Current Mode) to DCM (Discontinuous Current Mode), which requires a load capacitor.
     3, operating frequency down
     This is also a common phenomenon in the debugging process of the user. The down-clocking is mainly caused by two aspects: the ratio of the input voltage and the load voltage is small, and the system interference is large. For the former, be careful not to set the load voltage too high, although the load voltage is high, the efficiency will be high. For the latter, you can try the following aspects: a: set the minimum current to a smaller point; b: the clean point of the wiring, especially the sense of this critical path; c: choose the small point of the inductor or choose the inductor of the closed magnetic circuit. d: Add RC low-pass filter, this effect is a bit bad, C's consistency is not good, the deviation is a bit big, but for the lighting should be enough.
      In any case, there is no advantage in lowering the frequency, only the disadvantages, so it must be resolved.
     4, the choice of inductor or transformer
     Finally I talked about the key points. I haven't started yet. I can only say the effect of saturation. Many users react, the same drive circuit, no problem with the inductance produced by a, and the inductor current produced with b becomes smaller. In this case, look at the inductor current waveform. Some engineers did not notice this phenomenon and directly adjusted the sense resistor or the working frequency to reach the required current. This may seriously affect the service life of the LED. So, before the design, a reasonable calculation is necessary. If the parameters of the theoretical calculation and the debugging parameters are a little different, we must consider whether or not the frequency reduction and the transformer saturation.
     When the transformer is saturated, L will become smaller, resulting in a sharp increase in the peak current increase caused by the transmission delay, and then the LED peak current will increase. With the average current constant, you can only see the light decay.
     5, LED current size
     Everyone knows that if the LEDripple is too large, the LED lifetime will be affected, how much it will affect, and no one has ever said. Previously asked the LED factory this data, they said that within 30% can be accepted, but later not verified. It is recommended to try to control small points. If the thermal solution is not good, the LED must be derated. It is also hoped that experts can give specific indicators, or else they will influence the promotion of LED.
     Having said so much, it seems that LED driver design is not difficult, it must have a good idea. As long as the calculation before debugging, measurement during debugging, aging after debugging, I believe that anyone can engage in LED.